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实变函数:Lp空间 / 不等式

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不等式 #

tip

pppp' 为共轭指标, 若 fLp(E),gLp(E)f\in L^p(E),g\in L^{p'}(E), 则有

fg1fpgp,p>1\Vert fg\Vert_1\leqslant\Vert f\Vert_p\cdot \Vert g\Vert_{p'},\quad p>1
note

利用 exe^x 下凸, 得到不等式 a1/pb1/pap+bpa^{1/p}b^{1/p'}\leqslant \frac a{p}+\frac b{p'}.

a=f(x)pfpp,b=g(x)pgppa=\frac{|f(x)|^p}{\Vert f\Vert_p^p},b=\frac{|g(x)|^{p'}}{\Vert g\Vert_{p'}^{p'}}

可得

f(x)g(x)fpgp1pf(x)pfpp+1pg(x)pgpp\frac{|f(x)g(x)|}{\Vert f\Vert_p\cdot\Vert g\Vert_{p'}}\leqslant \frac 1 p \cdot\frac{|f(x)|^p}{\Vert f\Vert_p^p}+\frac 1{p'}\cdot\frac{|g(x)|^{p'}}{\Vert g\Vert_{p'}^{p'}}

对上式两侧积分可得

fg1fpgp1\frac{\Vert fg\Vert_1}{\Vert f\Vert_p\cdot\Vert g\Vert_{p'}}\leqslant 1

故不等式成立.

tip

pr\frac p rpr\frac {p'} r 为共轭指标, 即满足 1r=1p+1p\dfrac 1 r=\dfrac 1 p +\dfrac 1 {p'}, 若 fLp(E),gLp(E)f\in L^p(E),g\in L^{p'}(E), 则有

fgrfpgp\Vert fg\Vert_r\leqslant\Vert f\Vert_p\cdot \Vert g\Vert_{p'}
note

利用 Holder 不等式

Ef(x)g(x)rdx=Ef(x)rg(x)rdx(E(f(x)r)p/rdx)r/p(E(g(x)r)r/qdx)r/q\begin{aligned} & \int_E |f(x)g(x)|^r\text{d} x=\int_E |f(x)|^r |g(x)|^r\text{d} x\\ &\leqslant \left(\int_E (|f(x)|^r)^{p/r}\text{d} x\right)^{r/p}\left(\int_E(|g(x)|^r)^{r/q}\text{d} x\right)^{r/q} \end{aligned}

再对上式开 rr 次根号即可得到

fgrfpgq.\Vert fg\Vert_r\leqslant\Vert f\Vert_p\cdot\Vert g\Vert_q.
tip

f,gLp(E),p>1f,g\in L^p(E),p>1

f+gpfp+gp\Vert f+g \Vert_p\leqslant \Vert f \Vert_p+\Vert g \Vert_p
note
Ef(x)+g(x)pdxEf(x)+g(x)p1f(x)+g(x)dxEf(x)+g(x)p1f(x)dx+Ef(x)+g(x)p1g(x)dx\begin{aligned} &\int_E|f(x)+g(x)|^p\text{d} x\\ \leqslant & \int_E|f(x)+g(x)|^{p-1}\cdot|f(x)+g(x)|\text{d} x\\ \leqslant\int_E |f(x)+g(x)|^{p-1}\cdot|f(x)|\text{d} x \\ &+ \int_E |f(x)+g(x)|^{p-1}\cdot |g(x)|\text{d} x \end{aligned}

取共轭指标 ppp=pp1p'=\frac{p}{p-1} 对上式两个求和分别使用 Holder 不等式.

Ef(x)+g(x)p1f(x)dxf+gpp1+fp\int_E |f(x)+g(x)|^{p-1}\cdot|f(x)|\text{d} x\leqslant \Vert f+g\Vert_p^{p-1}+\Vert f\Vert_p

对另一部分同样如此, 再将 f+gpp1\Vert f+g\Vert_p^{p-1} 约去即可.

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